Fri Jun 13, 2008 3:55 am by tartle |
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I have 7 pegs on a board, 3 to the left have blue rings and three to the right have red rings, the centre peg is empty.
Advise in turn how l can get the 3 blue and the 3 red to opposite ends of the board. You can not move backwards. |
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Thu Jul 10, 2008 6:09 pm by Tyer |
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I shall show with letters:
AAA()BBB
AAAB()BB
AA()BABB
A()ABABB
ABA()ABB
ABABA()B
ABABAB()
ABAB()BA
AB()BABA
()BABABA
B()ABABA
BBA()ABA
BBABA()A
BBAB()AA
BB()BAAA
BBB()AAA
woo never had to write that out before but try with like pennies or something it does work. |
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Tue Nov 18, 2008 8:46 pm by Axomomma |
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[quote="tartle"]I have 7 pegs on a board, 3 to the left have blue rings and three to the right have red rings, the centre peg is empty.
Advise in turn how l can get the 3 blue and the 3 red to opposite ends of the board. You can not move backwards.[/quote]
While Tyer's answer is clearly impressive and well thought out and seems to involve a series of jumping one peg over the other, nothing was ever mentioned that would prevent one from simply removing ALL the pegs and placing them where you want them. :-) |
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