It's not like hes making these up himself, i've heard it before and if you have half a mind and read the explanation thoroughly, it makes sense. Tricky one though.
There is no extra money. Re: Two men paid $3.33 and the third paid $3.34 cents. $10/3=3.333. With the return of the one dollar to each person, that means that two men paid $4.33 and the third paid $4.34. The sum is therefore, $13.00 + $2.00 that the waiter pocketed makes $15.00
OMG!!!......i tried this about a million times.....no solution....and then i read the solution...........and take about 15 min to understand..............my brain is boiling!!!!
The men paid $15 for the meal. Then $5.00 was returned, so the meal cost 10.00. (So start with $10.00 bucks on the table and add $3.
10 + 3 = 13. The waiter has $2. So now the total is 13 + 2 = 15
It's very easy to do the math the right way, but the key is to reveal what error in logic was made when the problem asked why 12+2 doesnt equal 15. What sleight of hand makes this confusing? Explain why the 12+2 sounds logical.
You can set up these equations: Each customer has 1$ and paid 4$ for the meal. It gives 15$
Or..The meal costs 10$, they have 3 and the waiter has 2, it gives 15 again (suprisingly :-))
But adding 12 they don't have and 2 the waiter does have, make no sence and is not avalid mathematical operation.
One should add bucks they all together have (customers 3, the house 10 and the waiter 2) or they all together don't have (the sutomers 12 and the waiter 3)
@ 12+2 yes, because basically they said (15-3)+2=14 when they should have said (15-3)-2=10, 10+5=15. The waiter is still detracting from the receipt.
It's easy to see what about it is incorrect, but its harder to explain why.
A couple of people have touched on this, and they are quite right. What makes this puzzle so devilishly confuzzling (good word: I'm keepin' it) is the line that mentions that the three men effectively paid $4 each, making $12, and then we add the waiter's $2 to make $14, which is tantalizingly close to the original $15. Here's the logical sleight of hand: It *makes no sense* to add the waiter's $2 to the amount the men paid because his $2 is *already included* in that amount. Yes, they paid $12...the manager has $10 and the waiter has $2. This problem is invariably worded in such a way as to allow the illogical nature of adding the waiter's $2 to the amount the men paid to slip under your logical radar.
customers paid $15 so they no longer have $15
now the manager has $10 in hand
then waiter has $2
and finally $3 is returned to table
manager=10
Waiter=2
customers=3
Obviously the three contributed $10 after returning the $5. But the waiter returned only $3 to the three men and pocketed $2. So total would be $13. If you add $13 + $2 = $15
The 3 men paid $15 but got a $5 reduction hence $15 - $5 = $10. (Now the five is going to be returned)
The 3 men have paid the equivalent of $10 due to the $5 reduction (but the don't know it ) because the greedy waiter takes $2 of the $5 and gives the remaining $3 to the three men. $10 + $3 = $13. [this is the same as $15-$2]
Thus the men think they have got a $2 reduction which is actually in the waiter's pocket.
for crying out loud if you didnt get it thats okay there is no need to call people names, for the ones that did get it and are using names, when they dont get i mean come on i didnt get and i am still living my life goodnees sakes!!!!!!!!!!!!!!
our thought processes are the same whether we are 10 or 50. Any "problem" is what we see in our mind. what appears logical can be deceptive. What is important is perception: "the way we see things".
"Now, each of the men effectively paid $4, the total paid is therefore $12. Add the $2 in the waiters pocket and this comes to $14.....where has the other $1 gone from the original $15?"
But that $12 dollars already includes the waiter's "tip", so no need to count it twice. There is no extra dollar. Just $10 to the cafe, $2 to the waiter, and $3 to the men
$15 - $3 = $10 + $2? is that it?
CAN SOME1 PLZZZ EXPLAIN IT SIMPLY 4 ME!!!!!!!!!
10 + 3 = 13. The waiter has $2. So now the total is 13 + 2 = 15
2$ went for tip
and 3$ were redistributed back.
It dosen't make much sense to add 2$ (tip) to 12$ (food and tip) and then subtract it from 15$
Or..The meal costs 10$, they have 3 and the waiter has 2, it gives 15 again (suprisingly :-))
But adding 12 they don't have and 2 the waiter does have, make no sence and is not avalid mathematical operation.
One should add bucks they all together have (customers 3, the house 10 and the waiter 2) or they all together don't have (the sutomers 12 and the waiter 3)
It's easy to see what about it is incorrect, but its harder to explain why.
now the manager has $10 in hand
then waiter has $2
and finally $3 is returned to table
manager=10
Waiter=2
customers=3
10/3 = 3.3333 + 1.00 = 4.3333 * 3 = 13
13 + 2 = 15
Now if the waiter had not keep the 2 dollars
2/3 = .6667 more to each of the customers
3.3333 + 1.6667 = 5.00 + 10.00 = 15.00
The 3 men have paid the equivalent of $10 due to the $5 reduction (but the don't know it ) because the greedy waiter takes $2 of the $5 and gives the remaining $3 to the three men. $10 + $3 = $13. [this is the same as $15-$2]
Thus the men think they have got a $2 reduction which is actually in the waiter's pocket.
The first notion is pretty swaying.
But that $12 dollars already includes the waiter's "tip", so no need to count it twice. There is no extra dollar. Just $10 to the cafe, $2 to the waiter, and $3 to the men