Thu Jan 17, 2013 11:36 pm by tartle 


five cards have been laid out, all are between ace(1) and ten. Each card shows a different value. All four suits are represented. NO three of the cards form a consecutive sequence of numbers.
The total value of the red cards is the same as the total of the black cards.
The total vaule of hearts is 12.
The evenvalue cards have a total four higher than the sum of the oddvalue cards.
The club has a lower value than the spade. The lowest card is a diamond.
Find out which 5 cards have been dealt. 




Sun Apr 07, 2013 12:50 am by me 


2 of diamonds, 4 of hearts, 6 of hearts, 3 of clubs, 5 of spades 




Fri Jun 14, 2013 7:30 am by Hanna 


MY SOLUTION
6 of hearts plus four of hearts does not equal a total of 12.
I found two possible answers though. Maybe I'm doing something wrong.
Solution 1: 9 of hearts, 3 of hearts, 2 of diamonds, 8 of spades, and 6 of clubs
Solution 2: 7 of hearts, 5 of hearts, 2 of diamonds, 10 of spades, and 4 of clubs
Both seem to meet the criteria. 






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