Thu Jan 17, 2013 10:54 pm by tartle |
|
|
I have some square tiles. Half of them are black and the other ones are white. I arrange them so that the black ones form a rectangle and the white ones make a border around them one tile thick. I have no tiles left over. How many tiles do I have? |
|
|
|
|
Mon Mar 04, 2013 10:44 pm by Allstar |
|
|
[b]spoiler alert[/b]
48, 24 black and 24 white. The black rectangle is 4x6.[/b] |
|
|
|
|
Fri Jul 15, 2016 5:39 am by Dzallen |
|
|
There are only 2 solutions: 48 tiles with 4*6 black rectangle, or 60 tiles with 3*10 black rectangle
The difference in tiles between the white tiles and the outer most layer of the black rectangle is 8 tiles (2 tiles for each side). Therefore the inner black rectangle must have 8 tiles, which can be arranged as 2*4 or 1*8, giving the whole black rectangle as 4*6 or 3*10. |
|
|
|
|
|
|
All times are GMT
|
Page 1 of 1 |
|