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 Very Easy Logic Problems Mathematics....
 Mon Dec 07, 2015 11:26 am  by GmdAquaman Three men in a cafe order a meal the total cost of which is \$15. They each contribute \$5. The waiter takes the money to the chef who recognizes the three as friends and asks the waiter to return \$5 to the men. The waiter is not only poor at mathematics but dishonest and instead of going to the trouble of splitting the \$5 between the three he simply gives them \$1 each and pockets the remaining \$2 for himself. Now, each of the men effectively paid \$4, the total paid is therefore \$12. Add the \$2 in the waiters pocket and this comes to \$14.....where has the other \$1 gone from the original \$15? :idea: :?: :?: :!: :?: :!: :!: :twisted: :evil:
 Sat Dec 19, 2015 1:22 am  by ac4pic 3x = 15 (gave it to the waiter -> gives it to the chef) x = 5 (each paid) 3x = 10 (chef got this much left) x = 3.33.... (each one of them paid to the chef) The chef is done with. Now, how much do you pay the waiter? (They each pay 2 dollars) 3x = 2 x = (2/3) Each pay 66 cents to the waiter. ((chef) + (waiter))/3 = (total paid per person) 3.33 + .66 = 4 dollars They paid in total 4 dollars. 3x = 12 Now, they get the remaining 3 dollars. :D So, they saved 1/5 the money. Everyone wins! :D
 Sat Jan 07, 2017 11:21 am  by Saiyan0414 The men paid a total of 12\$ and the waiter keeps 2\$ for himself. Also when the chef returned 5\$ back he is left with 10\$. therefore, 10\$(chef) + 2\$(waiter) = 12\$ paid by the 3 men.[/list]
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