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 Very Difficult Logic Problems Falling Orbs Goto page Previous  1, 2, 3
 Thu Jul 21, 2016 9:57 am  by bathfilms Hi Dzallen, Yes, I see your point.. After reconsidering the problem, I have worked out that the optimum pseudo-binary splitting would yield a new answer of 21 drops: We start on floor 5 and then move to floor 10 or floor 1 (depending on ball survival or breakage respectively)... see the flow chart below: [Floor numbers] ..............................25..etc... ..........................20 ........................./...16...etc... ......................../ .....................15.... ..................../....\...12 .................10......11 ................/....\.......10 ............../.......\..7 ............5......4..6 ..............\...3......5 ...............\./..2 ................1 ..................0 This allows a maximum of 2 breakages. If the flow chart is extended, it shows that 21 drops are required to determine 1 to 100 floors inclusively. However, to my surprise this pseudo-binary splitting has not produced the minimum. Therefore I agree with the answer of 14 as described by others.
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