78. Cachers and Whackos Riddle I think all sane people are cachers and one third of all cachers are sane but half of all whackos are cachers with only one whacko that s sane If eight whackos are cachers and ninety are attending my ball how many cachers are neither sane nor whacko at all? Added 8 July 2010 Show Solution Solution: Let C be the total number of cachers. Since one third of cachers are sane, we have S = C/3. Half of the whackos are cachers, so W = 8 (whackos who are cachers). The total number of attendees is 90, which includes sane cachers, whackos, and others. The number of cachers who are neither sane nor whacko is C - S - W. Solving the equations gives us the answer.
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