Logic Puzzles


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Logic problems that require some dedicated thinking to solve.

1. The Missing Piece

Below the four parts have been reorganized. The four partitions are exactly the same in both arrangements. Why is there a hole?


Where does this hole come from?

The Missing Piece

The four pieces are exactly the same. Drag the pieces yourself, or press Rearrange to watch the pieces move into the other position.

Drag any piece, or press Rearrange.
Hint:

This is not an optical illusion. If you print out the puzzle, cut out the pieces and rearrange them, you get the exact same dilemma.

Solution:

The gradient of the teal hypotenuse is different than the gradient of the red hypotenuse.


2. Four Gallons

You have a three gallon and a five gallon measuring device. You wish to measure out four gallons.

Solution:

Fill the five gallon container. Pour all but two gallons into the three gallon container. Empty the three gallon container. Put the two remaining gallons from the five gallon container into the three gallon container. Fill the five gallon container one more time. Pour one gallon from the five gallon container by filling the three gallon container. Now the five gallon container contains four gallons.

I have an alternate answer for the Four Gallons problem. Fill up the 3-gallon and pour it into the 5-gallon. Again, fill up the 3-gallon and pour it into the 5-gallon. Now, 1 gallon will be left in the 3-gallon. Pour out all the water from the 5-gallon and fill it up with that one gallon. Now, measure 3 gallons and pour it into the 5-gallon to bring out 4.


3. The Islanders

There are two beautiful yet remote islands in the south pacific. The Islanders born on one island always tell the truth, and the Islanders from the other island always lie.

You are on one of the islands, and meet three Islanders. You ask the first which island they are from in the most appropriate Polynesian tongue, and he indicates that the other two Islanders are from the same Island. You ask the second Islander the same question, and he also indicates that the other two Islanders are from the same island.

You ask the third Islander whether the other two Islanders are from the same island as him. Can you guess what the third Islander will answer to the same question?

Solution:

Yes, the third Islander will say the other two Islanders are from the same island.


4. Five Gallons

You are mixing cement and the recipe calls for five gallons of water. You have a garden hose giving you all the water you need. The problem is that you only have a four gallon bucket and a seven gallon bucket and nether has graduation marks. Find a method to measure five gallons.

Solution:

Pour the four gallon bucket filled with water into the empty seven gallon bucket. Fill the four gallon bucket up again and poor as much as you can into the seven gallon bucket until the seven gallon bucket is fill. Now there is one gallon left in the four gallon bucket. Empty the seven gallon bucket and transfer the one gallon of water into the seven gallon bucket. Fill the four gallon bucket one more time, then pour the four gallons into the seven gallon bucket making which already has one gallon in it, making a total of five gallons.


5. Two Strings

You have two strings whose only known property is that when you light one end of either string it takes exactly one hour to burn. The rate at which the strings will burn is completely random and each string is different.

How do you measure 45 minutes?

Hint:

Don't burn your candles at both ends trying to solve this one.

Solution:

Light both the ends of the first string and one end of the second string. 30 minutes will have passed when the first string is fully burned, which means 30 minutes have burned off the second string. Light the end of the second string and when it is fully burned, 45 minutes will have passed.

Some people have difficulty grasping that when you light both ends of the first fuse, it will take 30 minutes to burn. Because the burning rate is random and unknown to you, you have no idea where the 30 minute mark is on the fuse. If you had an exact duplicate, then the 30 minute mark would be in the same place. It is probably not in the middle, but it is somewhere. If you burn both ends of a fuse it will not stop burning until it has reached this mark, which means 30 minutes is up.


6. The Cubes

A corporate businessman has two cubes on his office desk. Every day he arranges both cubes so that the front faces show the current day of the month.

What numbers are on the faces of the cubes to allow this?

Note: You can't represent the day "7" with a single cube with a side that says 7 on it. You have to use both cubes all the time. So the 7th day would be "07".

Hint:

1 & 2 must be on both cubes (11 & 22). So must one other number. 6=9 upside down.

Solution:

Cube One has the following numbers: 0, 1, 2, 3, 4, 5

Cube two has the following numbers: 0, 1, 2, 6, 7, 8

The 6 doubles as a 9 when turned the other way around.

There is no day 00, but you still need the 0 on both cubes in order to make all the numbers between 01 and 09.

Alternate solutions are also possible e.g. 
Cube One: 1, 2, 4, 0, 5, 6 
Cube Two: 3, 1, 2, 7, 8, 0

7. The Pot of Beans

A pot contains 75 white beans and 150 black ones. Next to the pot is a large pile of black beans.

A somewhat demented cook removes the beans from the pot, one at a time, according to the following strange rule: He removes two beans from the pot at random. If at least one of the beans is black, he places it on the bean-pile and drops the other bean, no matter what color, back in the pot. If both beans are white, on the other hand, he discards both of them and removes one black bean from the pile and drops it in the pot.

At each turn of this procedure, the pot has one less bean in it. Eventually, just one bean is left in the pot. What color is it?

Solution:

White. The cook only ever removes the white beans two at a time, and there are an odd number of them. When the cook gets to the last white bean, and picks it up along with a black bean, the white one always goes back into the pot.


8. The Pigeon

Two friends decide to get together; so they start riding bikes towards each other. They plan to meet halfway. Each is riding at 6 MPH. They live 36 miles apart. One of them has a pet carrier pigeon and it starts flying the instant the friends start traveling. The pigeon flies back and forth at 18 MPH between the 2 friends until the friends meet.

How many miles does the pigeon travel?

Hint:

You must presume that the pigeon can go from 0 to 18 mph instantaneously, plus also turn around instantaneously.

Solution:

54.

It takes 3 hours for the friends to meet; so the pigeon flies for 3 hours at 18 MPH = 54 miles.


9. The Lightbulb

There is a lightbulb (incandescent, it's currently off) in an upstairs room. You are downstairs, standing next to a panel of three light switches (all of them in the off position). One of them controls the lightbulb. The other two don't do anything. You must figure out which switch controls the bulb, with some restrictions.

1) You can do whatever you want to the lightswitches, as long as it's either turning them on or turning them off.
2) After fiddling with the lightswitches, you can go upstairs and check the bulb.
3) You cannot see the bulb nor any light shining from it from where you're initially standing.
4) You cannot make multiple trips up and down the stairs.
5) The lamp is in the ceiling and you don't have a ladder.
6) You are a mutant with 15-foot-long arms, so #5 is moot.

So, you fiddle with the switches, you walk upstairs and check the bulb, and then you immediately decide which switch controls the bulb.

How do you do it?

Solution:

Flick Switch A. Leave it on for ten minutes. Turn it off. Flick Switch B. Leave it on. Leave Switch C off. Go up to the room. If the bulb is off but warm, it is Switch A. If the bulb is on, it is Switch B. If it is off, and cold, it is C.


10. On the Top Floor of a Castle Lives a Princess.

A princess occupies the entire top floor of a castle. The floor contains 17 bedrooms arranged in a straight line. Each bedroom has
• an interior door to each adjacent bedroom, and
• an exterior door that opens onto a common corridor.

Every night, just after midnight, the princess moves through an interior door to one of the two neighbouring bedrooms and then spends the entire next day there. She never stays in the same room two nights in a row and she never skips a room.

A prince arrives wishing to marry her. Each morning, before the princess makes her nightly move, he may knock on exactly one exterior door. If the princess is in that bedroom she will open the door and agree to marry him; otherwise nothing happens and the day is lost.

The prince must return to his kingdom after 30 days, so he has at most 30 knocks. Knowing the princess’s routine but not her initial location, can the prince guarantee success? If so, describe an explicit day-by-day strategy.

Solution:

Label the bedrooms 1 through 17 from left to right. The prince never needs to knock on rooms 1 or 17; instead he proceeds as follows.

Days 1–15 : knock on room 2, then 3, 4, …, up to room 16.
Day 16 : knock on room 16 again.
Days 17–30 : knock on room 15, then 14, 13, …, back down to room 2.

This schedule uses exactly 30 attempts (room 16 is visited twice) and is guaranteed to succeed.

Why it works
Suppose the princess starts in room k on the morning of day 1.

• While the prince is moving to the right (days 1–15), he advances one room each day, exactly as the princess does. The difference k − P (where P is the room he knocks on) therefore changes by 0 or ±2 each day, so its parity is preserved. In particular the princess can never pass the prince—she can only stay the same distance away or get closer. By the morning of day 15 the prince is at room 16, so if the princess started in any even-numbered room (2, 4, …, 16) he must already have found her.

• If instead she started in an odd-numbered room, then on day 16 she is in an even-numbered room (because she moves every night). Day 16 is the moment the prince stops and knocks on room 16 a second time; from that day on he reverses direction and again moves in lock-step with the princess. The same “cannot pass” argument now applies to the left-moving phase, and the prince must catch the princess no later than day 30 when he knocks on room 2.

Thus, regardless of her initial position, the princess will open the door within 30 days, and the prince is assured of winning her hand.


11.

What costs a dog?

Achmed and Ali are camel-drivers, and on one day they decided to quit their job. They wanted to become shepherds. So they went to the market and sold all their camels. The amount of money (dinars) they received for each camel is the same as the total of camels they owned. For that money, they bought as many sheep as possible at 10 dinars a sheep. For the money that was left, they bought a goat.
On their way home, they got in a fight and decided to split up. When they divided the sheep, there was one sheep left. So Ali said to Achmed, "I take the last sheep, and you can get the goat." "That's not fair," said Achmed, "a goat costs less than a sheep." "Ok," Ali said, "then I will give you one of my dogs, and then we are even." And Achmed agreed.

How much does a dog cost?

Solution:

The goat costs 6 dinars, which is the price of a sheep minus the value of the dog. Since Ali took the last sheep, he owes Achmed a sheep's worth of value. Therefore, the dog must be valued at 4 dinars, making it equal in value to the difference between a sheep and a goat.


12.

A man needs to go through a train tunnel.

A man needs to go through a train tunnel. He starts through the tunnel and when he gets 1/4 the way through the tunnel, he hears the train whistle behind him. You don't know how far away the train is, or how fast it is going, (or how fast he is going). All you know is that
If the man turns around and runs back the way he came, he will just barely make it out of the tunnel alive before the train hits him.
If the man keeps running through the tunnel, he will also just barely make it out of the tunnel alive before the train hits him.
Assume the man runs the same speed whether he goes back to the start or continues on through the tunnel. Also assume that he accelerates to his top speed instantaneously. Assume the train misses him by an infinitesimal amount and all those other reasonable assumptions that go along with puzzles like this so that some wanker doesn't say the problem isn't well defined.
How fast is the train going compared to the man?

Solution:

The train is moving twice the speed of the man. When the man runs back to the entrance of the tunnel, he covers 1/4 of the tunnel's length, while the train covers the entire length of the tunnel in the same time. Therefore, the train must be traveling at a speed that is double the man's speed to ensure both reach their respective exits at the same moment.


13.

Line of Geniuses

This question is from my geometry class, it only involves logic not probability. Please help me solve this! It is only middle school, so I don't think it would be TOO hard. Anyways, here it is. Reply as soon as possible, please.
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Three geniuses stand in a line (one behind the other). Each can see only to the front, so the rear person can see the middle and the front, the middle person can see the front, and the genius in the front cannot see anyone.

You have five hats. Two are white, and three are red. You blindfold the three geniuses, who are utterly truthful, and put a hat--at random--on the head of each. Then you hide the other two hats and remove the blindfolds.

You then ask each genius to name the color of his hat (which he cannot see).

The rear one says, "I don't know." The middle one says, "I don't know." Then the front one says, "I know."

What color hat is the front genius wearing?????? How does he know with 100% certainty what color hat it is?????

Solution:

The front genius is wearing a red hat. The rear genius, seeing the hats of the two in front, would only say 'I don't know' if he saw one red and one white hat, as he could not determine his own hat color. The middle genius, knowing the rear genius saw two hats and still said 'I don't know', concludes that he must be wearing a red hat. Therefore, the front genius deduces that he must also be wearing a red hat.


14. Three Lightbulbs.

You are standing outside a basement door, Down the stairs, there are 3 light bulbs.

Next to you, are 3 switches. You cannot see the lights from upstairs, and you must decide which switch controls which lightbulb by going downstairs once.

How do you do this?

Solution:

Turn on the first switch and leave it on for about 10 minutes. Then, turn it off and turn on the second switch. Go downstairs. The bulb that is on corresponds to the second switch, the bulb that is off but warm corresponds to the first switch, and the bulb that is off and cool corresponds to the third switch.


15.

The Island of Baal of All the Islands of Knights and Knaves

The Island of Baal
Of all the islands of knights and knaves, the island of Baal is the weirdest and most remarkable. This island is inhabited exclusively by humans and monkeys. The monkey, as well as every human, is either a knight or a knave.
In the dead center of this island stands the Temple of Baal, one of the most remarkable temples in the entire universe. The high priests are metaphysicians, and in the Inner Sanctum of the temple can be found a priest who is rumored to know the answer to the ultimate mystery of the universe; why there is something instead of nothing.
Aspirants to the Sacred Knowledge are allowed to visit the Inner Sanctum, provided that they prove themselves worthy by passing three series of tests. I learned all these secrets, incidentally, by stealth: I had to enter the temple disguised as a monkey. I did this at great personal risk. Had I been caught, the penalty would have been unimaginable. Instead of merely annihilating me, the priests would have changed the very laws of the universe in such a way that I could never have been born!
Well, a philosopher who was searching for the answer to the question, "Why is there something rather than nothing?" arrived on the island of Baal and agreed to try the tests. The first series took place on three consecutive days in a huge room called the Outer Sanctum. In the center of the room a cowled figure was seated on a golden throne. He was either a human or a monkey, and also a knight or a knave. He uttered a sacred sentence, and from this sentence the philosopher had to deduce exactly what he was, whether a knight or a knave, and whether a human or a monkey.
The First Test
The speaker said, "I am either a knave or a monkey." Exactly what is he?
The Second Test
The speaker said, "I am a knave and a monkey." Exactly what is he?
The Third Test
The speaker said, "I am not both a monkey and a knight." What is he?

Solution:

In the First Test, the speaker must be a knight and a monkey because if he were a knave, the statement would be false, which contradicts the nature of knaves. So, the First Subject = Monkey Knight.

In the Second Test, the speaker cannot be a knight, as a knight cannot claim to be a knave; thus, he is a knave and a human. So, the Second Subject = Human Knave.

In the Third Test, the speaker cannot be a knave, as that would make him a lying knight; therefore, he must be a knight and cannot be a monkey. So, the Third Subject = Human Knight.


16. Two Friends, Whom We Will Call Arthur and Robert, Were

Two friends, whom we will call Arthur and Robert, were curators at the Museum of American History. Both were born in the month of May, one in 1932 and the other a year later.

Each was in charge of a beautiful antique clock. Both of the clocks worked pretty well, considering their ages, but one of them lost ten seconds an hour and the other gained ten seconds an hour.

On one bright day in January, the two friends set both clocks right at exactly 12 noon.

``You realize,'' said Arthur, ``that the clocks will start drifting apart, and they won't be together again until---let's see---why, on the very day you will be 47 years old. Am I right?''

Robert then made a short calculation. ``That's right!'' he said.

Who is older, Arthur or Robert?

Solution:

Arthur is actually the younger friend, born in May 1933, while Robert was born in May 1932. The clocks will drift apart due to one gaining and the other losing time, and they will align again when Robert turns 47 on May 1, 1979, which means the clocks were set right on January 31, 1979, in a non-leap year.


17.

Brown, Jones & Smith are suspected of income tax evasion.

Brown, Jones & Smith are suspected of income tax evasion. They testify, under oath as follows
Brown: Jones is guilty & Smith is innocent
Jones: If Brown is guilty, then so is Smith
Smith: I am innocent but at least one of the others is guilty.
a) Assuming everybody told the truth who is or are innocent or guilty?
b) Assuming the innocent told the truth & guilty lied who is or are innocent or guilty?

Solution:

Assuming everyone told the truth, Jones is guilty while Brown and Smith are innocent. Assuming the innocent tell the truth and the guilty lie, Brown and Smith are guilty while Jones is innocent.


18.

You want to go to a city where everybody always is truthful.

You want to go to a city where everybody always says the truth. On your way there, you reach a crossroad. On one side is the city where everyone says the truth; on the other is a city where everyone lies. There is a man at the crossroad that comes from one of the cities. You do not know from which city the man comes, and you can only ask him one question to find out where the city of truth is. What do you ask him?

Solution:

You can ask the man, 'Which city do you come from?' If he tells the truth, he will point to the city of Truth. If he lies, he will also point to the city of Truth. Therefore, you should go towards the city he indicates.


19.

There are 2 rooms, one with a gold treasury.

There are 2 rooms, one with a gold treasury and another with deadly snakes. Each room is guarded by a security. Among the two, one always speaks the truth and the other false. You can ask only one question to either of the security to identify the room with gold.

Solution:

You can ask either guard, 'If I were to ask the other guard which room has the gold, what would he say?' If you ask the truth-teller, he will truthfully report the false guard's lie, leading you to the room with snakes. If you ask the liar, he will lie about the truth-teller's answer, also pointing you to the room with snakes. Therefore, you should choose the opposite room to find the gold treasury.


20.

In Ancient Times, Four Mathematicians Discovered a Game of L

In ancient times, four mathematicians discovered a game of logic. The four people were Mr. Macdonald, Mr. Franke, Mr. Kennedy, and Mrs. Sharma. Mr. Kennedy seated the other three people one behind the other so that Mr. Macdonald saw Franke and Sharma and so that Franke and Sharma saw no one.
Mr. Kennedy had 5 hats which he showed to the mathematicians. Three of the hats were grey and 2 white. Mr. Kennedy put a hat on each person's head and hid the remaining two hats in the box. "What colour is your hat, Mr. Macdonald?" asked Mr. Kennedy. Mr. Macdonald did not know. Mr. Franke did not know the colour of his hat either when asked.
Mrs. Sharma, who couldn't see any hats at all, gave the correct answer when asked the colour of her hat. What was the colour of her hat and how did she figure it out?

Solution:

Mrs. Sharma's hat must be grey. Mr. MacDonald could not determine his hat color, which means he saw either one grey and one white hat or two grey hats on Mr. Franke and Mrs. Sharma. Mr. Franke, seeing Mrs. Sharma, could not determine his hat color either, indicating that Mrs. Sharma must be wearing a grey hat. Since Mr. Franke could not confidently identify his hat color, Mrs. Sharma deduced that her hat must be grey.


21. Paying for 7 Days With 2 Cuts

A landlady permitted the students to rent her apartment with the following condition: the student will pay her 7 golden chain for her 7 days stay at her apartment, she is only allowed to cut the chain twice but the student is obliged to pay one chain daily for 7 days. How is it possible?

Hint:

Think about how to divide the chains to meet the daily payment requirement.

Solution:

The landlady can cut the chain into three pieces: one piece of 1 chain, one piece of 2 chains, and one piece of 4 chains. On each day, the student can pay as follows:

  • Day 1: Pay 1 chain
  • Day 2: Return 1 chain and pay 2 chains (total 2 chains)
  • Day 3: Return 2 chains and pay 4 chains (total 4 chains)
  • Day 4: Pay 1 chain
  • Day 5: Return 1 chain and pay 2 chains (total 2 chains)
  • Day 6: Return 2 chains and pay 4 chains (total 4 chains)
  • Day 7: Pay 1 chain

22. Digit-Wise Subtraction Code

In a secret code, every digit of a number is replaced independently according to a fixed rule. For example:

555555555 → 222222222

Using the same rule, what is the coded form of the number 89898989898?

Hint:

Compare each corresponding digit in the example pair; what single arithmetic operation turns a 5 into a 2?

Solution:

The code subtracts 3 from each digit: 8 → 5 and 9 → 6. Applying this to every digit of 89898989898 gives 56565656565.


23. Identify the Lighter Ball

There are 9 similar looking balls with the same weight, but 1 among the 9 balls has relatively lesser weight. You are allowed to use a balance twice. How do you identify the ball with lesser weight?

Hint:

Try to divide the balls into groups to minimize the number of comparisons.

Solution:

1. Divide the 9 balls into 3 groups of 3 balls each (let's call them Group A, Group B, and Group C).
2. Weigh Group A against Group B.
3. If one group is lighter, the lighter group contains the lighter ball. If they balance, the lighter ball is in Group C.
4. Take the group that contains the lighter ball (3 balls) and weigh 2 of them against each other.
5. If one is lighter, that is the lighter ball. If they balance, the remaining ball is the lighter one.


24. Socks in the Dark Drawer

Ready to go, the light went out, and they have run out of matches to light a candle. Juan still needs to put on his socks. He thinks about taking them and putting them on later in a lit place. He has them in a drawer where there are 20 loose black socks and 20 loose blue socks. How many socks should he take to ensure he has a pair of the same color?

Hint:

Consider the worst possible situation when choosing the socks.

Solution:

Juan must bring 3 socks. This way, he ensures that he has at least one pair of the same color, since there are only two colors available.


25. Find the Right Switch in One Trip

Near the front door on the ground floor there are three unlabeled switches. One—and only one—of them controls the ceiling light in a room on the fourth floor. You would like to determine which switch it is, but you want to climb the stairs only once.

How can you identify the correct switch with a single trip upstairs?

Hint:

The bulb does more than give off light when it is on.

Solution:

Turn on the first switch and leave it on for about 10 minutes. This will allow the bulb, if connected, to heat up. After 10 minutes, turn the first switch off and immediately turn on the second switch. Now walk upstairs.

• If the light is on, it is controlled by the second switch.
• If the light is off but the bulb is warm to the touch, it is controlled by the first switch (which was on long enough to heat the bulb).
• If the light is off and the bulb is cool, it must be controlled by the third switch.

Thus you discover the correct switch with only one trip upstairs.


26. Family Tree Confusion

A man is standing in front of a picture of a man. Then he said Brothers and Sisters have I none but the father of this man (while pointing at the picture) is the son of my father. Who is in the picture?

Hint:

Think about the relationships and who the speaker is referring to.

Solution:

The man in the picture is the speaker's son.


27. Password Clue at the Club

At a club people were only allowed to enter if you know their password. Fatso wanted to enter but he didn't know the password so he stood just by the corner so that he can get the clue to the password. First person got at the door and the doorman said twelve and he said six and he got in, the next person came and the doorman said six and he said three and he was in. Fatso thought he got the clue and he went to the door. The doorman said ten and obviously Fatso said five and he was kicked out. What do you think was the password and why?

Hint:

The answer is related to the number of letters in the words spoken.

Solution:

The password is the number of letters in the number spoken by the doorman. For example, 'twelve' has six letters, 'six' has three letters, and 'ten' has three letters. Fatso incorrectly assumed it was half the number instead of counting the letters.


28. Family River Crossing with a 60 kg Boat Limit

Rajan (60 kg), his wife (40 kg) and their son (20 kg) need to cross a river in a small rowing boat. There is no boatman: anyone in the boat must do the rowing.

The boat can carry at most 60 kg at a time.

How can all three family members reach the opposite bank without exceeding the weight limit at any point?

Hint:

Notice that the wife and son together weigh exactly the boat's limit. Use them as the regular ferry crew so the boat can keep coming back for Rajan.

Solution:

Label the starting bank A and the far bank B. Each numbered line shows who is in the boat and the direction of travel.

  1. Wife + Son (40 + 20 = 60 kg) row from A to B.
  2. Son (20 kg) rows back from B to A, leaving the wife on bank B.
  3. Rajan (60 kg) rows alone from A to B.
  4. Wife (40 kg) rows back from B to A, joining the son.
  5. Wife + Son (60 kg) row together from A to B.

All three—Rajan, his wife, and their son—are now safely on bank B, and the weight limit was never exceeded.


29. Measuring One Gallon

A milkman has 2 empty jugs: a 3-gallon jug and a 5-gallon jug. How can he measure exactly one gallon without wasting any milk?

Hint:

Consider filling the jugs in different ways to achieve the desired measurement.

Solution:

1. Fill the 3-gallon jug completely from the milk supply.

2. Pour from the 3-gallon jug into the 5-gallon jug until the 5-gallon jug is full. This will leave you with 1 gallon in the 3-gallon jug.


30. Identifying Hidden Numbers on Cards

You are shown five cards lying on a table (so you can only see one side of each of the five cards). Each card has a single positive integer printed on each side of the card (they may or may not be repeated). The numbers that you can see are: 1, 2, 3, 4, and 5. How many cards must you turn over to completely verify the statement any card that has a 2 on one side has a 5 on the opposite side?

Hint:

Consider which cards could potentially violate the statement if they are not checked.

Solution:

You need to turn over the card showing 2 and the card showing 1. Turning over the 2 checks if there is a 5 on the opposite side, and turning over the 1 checks that it does not have a 2 on the other side.


31. Finding the Lighter Iron Ball

There are 4 iron balls, one with a comparatively little less weight than others which we cannot find by carrying it on the hand. When a beam balance (common balance) is given and only 2 chances are given to find the less weight ball. How will you do it?

Solution:

Label the balls A, B, C and D.

First weighing: put A and B in the left pan and C and D in the right pan.

The pan that rises (is lighter) holds the defective pair; the other pair is known to be normal.

Second weighing: take the two balls from the lighter pan and weigh them against each other.

The pan that rises now shows the single lighter ball—this is the ball with the lesser weight.


32. Ring Movement Puzzle

I have 7 pegs on a board, 3 to the left hand blue rings and three to the right have red rings, the centre peg is empty. How I can get the 3 blue and the 3 red to opposite ends if the board. You cannot move backwards.

Ring Peg Puzzle

Move the blue rings to the right and the red rings to the left. No moving backwards.

1
2
3
_
4
5
6
7
Start: B B B _ R R R
Goal: R R R _ B B B
Solution:

Ring Peg Puzzle Solution

Blue rings move only right. Red rings move only left. A ring may move one space or jump over one ring.

Start: B B B _ R R R
Click Next to begin.
  1. Blue: 3 → 4
  2. Red: 5 → 3
  3. Red: 6 → 5
  4. Blue: 4 → 6
  5. Blue: 2 → 4
  6. Blue: 1 → 2
  7. Red: 3 → 1
  8. Red: 5 → 3
  9. Red: 7 → 5
  10. Blue: 6 → 7
  11. Blue: 4 → 6
  12. Blue: 2 → 4
  13. Red: 3 → 2
  14. Red: 5 → 3
  15. Blue: 4 → 5

33. Race Position Riddle

I am in a race and I overtake the second person. What place am I in now?

Hint:

If you overtake the second person, think about who is in front of them.

Solution:

You are in second place.


34. How Far Is the Fall?

In a hotel each story is exactly 10 feet high. From ground level to the floor of the 3rd story is therefore 30 feet, and from ground level to the 10th story is 100 feet.

Using the same measurement, how far is it from the ground to the floor of the 20th story?

Hint:

Assume that every floor adds the same vertical distance.

Solution:

Since each story adds 10 feet of height, the distance from the ground to the floor of the nth story is 10 × n feet. For n = 20 this is 10 × 20 = 200 feet.


35. Surviving Two Hours in a Submerged Car

A man was driving alone when he lost control of his car at high speed. The vehicle crashed through a fence, tumbled down a steep ravine, and finally splashed into a fast-flowing river. With one arm broken, the driver was unable to release his seat belt and escape before the car sank to the bottom.

Rescuers arrived two hours later and hauled the car to the surface. To their surprise, the man was still inside—and still alive. How did he manage to survive two hours underwater?

Hint:

Think about what might have remained inside the car even after it sank.

Solution:

When the car hit the water, its doors and windows remained closed. As it settled on the riverbed, only part of the passenger compartment filled with water; the rest remained an air pocket. Strapped in his seat, the driver could breathe this trapped air, giving him enough oxygen to stay alive until rescuers arrived two hours later.


36. Dividing Eggs Among Sons

A man has three sons but he wants to have a daughter, however, in order to give him a daughter, God asks him how to divide seven eggs equally to three sons.

Solution: None

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