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Comments (24)
Anonymous
7 April 2007
Your solution to the scale puzzle is flawed. You stated to use the scale only once, but your solution implies using it multiple times. Please reconsider your approach.
Anonymous
6 December 2009
I don't follow the solution to "Flipping Coins". Can you explain it in a bit more detail?
Anonymous
6 December 2009
I don't follow the solution to 'Flipping Coins'. Can you explain it in a bit more detail?
Anonymous
13 December 2009
I am not sure that the solution given for this problem is correct. Consider the situation where the first pile contains 5 heads and 5 tails, and the second set contains 4 heads and 6 tails. Flipping the coins in the first pile would result in a pile with 5 of each coin, which are not two piles containing the same number of heads and tails.
Anonymous
16 December 2009
I've noticed that the solution proposed to 'Flipping Coins' seems incorrect. To create two groups with the same number of heads, one must separate a group of 10 coins and flip them all.
Anonymous
24 December 2009
The question about flipping coins is incorrect. There should be 20 coins, 10 heads and 10 tails, instead of 100 coins for the solution to be correct.
Anonymous
30 December 2009
Problem #7, Flipping Coins, is wrong. Two groups of 10 coins chosen at random does not guarantee that for every tail accounted for in one group of ten, there is a head in the other group of ten.
Anonymous
30 December 2009
The method described for flipping coins does not guarantee equal heads and tails. The original problem should be reviewed for accuracy.
Anonymous
25 January 2010
Pertaining to the Flipping Coins puzzle, there are a hundred coins sitting on the table, ten are currently heads and ninety are currently tails. You must create two sets of coins, each set must have the same number of heads.
Anonymous
25 January 2010
The solution to the Flipping Coins puzzle is incorrect. You cannot create two sets with the same number of heads and tails if one set has 10 tails and the other has 9 tails.
Anonymous
27 January 2010
The solution to 'Flipping Coins' doesn't make sense to me. If you don't know which are heads or tails to begin with, then the selection for each group of 10 is random. Flipping one group wouldn't give the same number of heads and tails.
Anonymous
3 February 2010
It seems to me that the puzzle has no solution. I tried the solution offered and something seems wrong to me. It says "Create two sets of ten coins" but we don't know if they are heads or tails.
Anonymous
3 February 2010
I tried to solve 'Flipping Coins' and it seems to have no solution. If we randomly pick 1 head and 9 tails in one group and 2 heads and 8 tails in the other, flipping one group won't give the same number of heads and tails.
Anonymous
5 February 2010
The solution to the Flipping Coins puzzle is to create two sets of ten coins. Flip the coins in one of the sets over, and leave the coins in the other set as they are.
Anonymous
10 February 2010
The puzzle 'Flipping Coins' is incorrectly stated. The correct wording should be that you want to end up with two groups with the 'same number of heads' as opposed to the 'same number of heads and tails.' Tails shouldn't matter.
Anonymous
13 February 2010
The answer to puzzle #7 does not make sense. With 90 tails and 10 heads, forming two sets with equal heads and tails is impossible.
Anonymous
2 March 2010
The logic in number 7 seems flawed. If one set has all tails and the other has a mix of heads and tails, flipping them will not result in matching sets.
Anonymous
22 March 2010
The Flipping Coins problem is unsolvable and the solution is nonsense. Has this been worded incorrectly?
Anonymous
1 December 2010
The solution proposed to 'Flipping Coins' seems incorrect. It should involve separating a group of 10 coins and flipping them to ensure both sets have the same number of heads.
Anonymous
6 December 2010
I've noticed that the solution proposed to 'Flipping Coins' is incorrect, or at least it seems so to me. I know this problem with a bit different conditions: one must create two arbitrary groups of coins with the same number of heads.
Anonymous
6 December 2010
The solution proposed to 'Flipping Coins' seems incorrect. I believe that to create two groups of coins with the same number of heads, one must separate a group of 10 coins and flip them all. This way, the number of heads will be the same as in the remaining set of 90.
Anonymous
27 November 2012
The solution to the Flipping Coins puzzle either does not work, or I don't understand it. If you flip over ten coins, you are not necessarily going to get the same amount of heads and tails as the other pile.
Anonymous
27 November 2012
The solution to 'Flipping Coins' doesn't make sense to me. If you don't know which are heads or tails to begin with, then the selection for each group of 10 is random. There are many possibilities for each group and I don't see how flipping all of the coins in one group will make them the same.
Anonymous
27 November 2012
The Flipping Coins puzzle is incorrectly stated, and your solution doesn't work. If one of my groups has 1 head and 9 tails, and the other has 2 heads and 8 tails, flipping all of one group over will not make them match.
Comments (24)
Your solution to the scale puzzle is flawed. You stated to use the scale only once, but your solution implies using it multiple times. Please reconsider your approach.
I don't follow the solution to "Flipping Coins". Can you explain it in a bit more detail?
I don't follow the solution to 'Flipping Coins'. Can you explain it in a bit more detail?
I am not sure that the solution given for this problem is correct. Consider the situation where the first pile contains 5 heads and 5 tails, and the second set contains 4 heads and 6 tails. Flipping the coins in the first pile would result in a pile with 5 of each coin, which are not two piles containing the same number of heads and tails.
I've noticed that the solution proposed to 'Flipping Coins' seems incorrect. To create two groups with the same number of heads, one must separate a group of 10 coins and flip them all.
The question about flipping coins is incorrect. There should be 20 coins, 10 heads and 10 tails, instead of 100 coins for the solution to be correct.
Problem #7, Flipping Coins, is wrong. Two groups of 10 coins chosen at random does not guarantee that for every tail accounted for in one group of ten, there is a head in the other group of ten.
The method described for flipping coins does not guarantee equal heads and tails. The original problem should be reviewed for accuracy.
Pertaining to the Flipping Coins puzzle, there are a hundred coins sitting on the table, ten are currently heads and ninety are currently tails. You must create two sets of coins, each set must have the same number of heads.
The solution to the Flipping Coins puzzle is incorrect. You cannot create two sets with the same number of heads and tails if one set has 10 tails and the other has 9 tails.
The solution to 'Flipping Coins' doesn't make sense to me. If you don't know which are heads or tails to begin with, then the selection for each group of 10 is random. Flipping one group wouldn't give the same number of heads and tails.
It seems to me that the puzzle has no solution. I tried the solution offered and something seems wrong to me. It says "Create two sets of ten coins" but we don't know if they are heads or tails.
I tried to solve 'Flipping Coins' and it seems to have no solution. If we randomly pick 1 head and 9 tails in one group and 2 heads and 8 tails in the other, flipping one group won't give the same number of heads and tails.
The solution to the Flipping Coins puzzle is to create two sets of ten coins. Flip the coins in one of the sets over, and leave the coins in the other set as they are.
The puzzle 'Flipping Coins' is incorrectly stated. The correct wording should be that you want to end up with two groups with the 'same number of heads' as opposed to the 'same number of heads and tails.' Tails shouldn't matter.
The answer to puzzle #7 does not make sense. With 90 tails and 10 heads, forming two sets with equal heads and tails is impossible.
The logic in number 7 seems flawed. If one set has all tails and the other has a mix of heads and tails, flipping them will not result in matching sets.
The Flipping Coins problem is unsolvable and the solution is nonsense. Has this been worded incorrectly?
The solution proposed to 'Flipping Coins' seems incorrect. It should involve separating a group of 10 coins and flipping them to ensure both sets have the same number of heads.
I've noticed that the solution proposed to 'Flipping Coins' is incorrect, or at least it seems so to me. I know this problem with a bit different conditions: one must create two arbitrary groups of coins with the same number of heads.
The solution proposed to 'Flipping Coins' seems incorrect. I believe that to create two groups of coins with the same number of heads, one must separate a group of 10 coins and flip them all. This way, the number of heads will be the same as in the remaining set of 90.
The solution to the Flipping Coins puzzle either does not work, or I don't understand it. If you flip over ten coins, you are not necessarily going to get the same amount of heads and tails as the other pile.
The solution to 'Flipping Coins' doesn't make sense to me. If you don't know which are heads or tails to begin with, then the selection for each group of 10 is random. There are many possibilities for each group and I don't see how flipping all of the coins in one group will make them the same.
The Flipping Coins puzzle is incorrectly stated, and your solution doesn't work. If one of my groups has 1 head and 9 tails, and the other has 2 heads and 8 tails, flipping all of one group over will not make them match.
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