This is a classic economics problem that even economists get wrong!

The answer is none.
This is a terrible proposition for both you and me.

From my perspective, if I have a hundred people playing, I am losing 5% each round.

From your perspective, unless you are the lucky ten percent (~13.6%), you are losing 5% each round.

Here is the math behind it.

1. House perspective: expected value

Each round, the player’s bankroll is multiplied by:

Heads: ×1.5
Tails: ×0.6

Expected multiplier:

0.5 × 1.5 + 0.5 × 0.6

= 0.75 + 0.30

= 1.05

So the player gains 5% in expected value per round.

That means the house loses 5% in expected value per round.

After 100 rounds, expected player bankroll is:

$10,000 × 1.05^100 ≈ $1,315,013

So from the house’s perspective, this is a terrible game to offer.

2. Player perspective: compound growth

For the player, expected value is misleading because the whole bankroll is being compounded.

The compound-growth multiplier is the geometric mean:

sqrt(1.5 × 0.6)

= sqrt(0.9)

≈ 0.9487

So the typical player loses:

1 - 0.9487 = 0.0513

or about:

5.13% per round

That is why the player’s typical outcome is bad even though the expected value is positive.

3. After 100 rounds

If the player gets H heads and 100 - H tails, final bankroll is:

$10,000 × 1.5^H × 0.6^(100-H)

To finish ahead, they need:

1.5^H × 0.6^(100-H) > 1

Take logs:

H ln(1.5) + (100 - H) ln(0.6) > 0

Solve:

H > 55.749...

So the player needs at least:

56 heads out of 100

The probability of getting 56 or more heads with a fair coin is:

P(H ≥ 56) ≈ 13.6%

So:

About 13.6% of players win.
About 86.4% of players lose.